On 28/03/13 15:25, Wolfgang Maier wrote:
Dear all, with
a=list(range(1,11))
why (in Python 2.7 and 3.3) is this explicit for loop working:
for i in a[:-1]:
a.pop() and a
giving:
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5]
[1, 2, 3, 4]
[1, 2, 3]
[1, 2]
[1]
but the equivalent comprehension failing:
[a.pop() and a for i in a[:-1]]
giving:
[[1], [1], [1], [1], [1], [1], [1], [1], [1]]
???
Especially, since these two things *do* work as expected:
[a.pop() and a[:] for i in a[:-1]]
[a.pop() and print(a) for i in a[:-1]] # Python 3 only
Thanks for your help,
Wolfgang
With the for loop the list is printed each time you pop an element. With
the list comprehension all but one of the elements are popped before the
string representation of the resulting list (containing several
references to a) is printed.
The two list comprehensions that you say "work" behave differently
because the first contains copies of a (which are unaffected by
subsequent pops), and the second because (I imagine) it does something
similar to,
[a.pop() and repr(a) for i in a[:-1]]
on 2.7 (I haven't migrated to 3 yet). i.e. The list contains a
representation of a after each element is popped.
Duncan
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