In article <5157e6cc$0$29974$c3e8da3$54964...@news.astraweb.com>, Steven D'Aprano <steve+comp.lang.pyt...@pearwood.info> wrote:
> For what it's worth, that last intermediate result (two to the power of > the 489-digit number) has approximately a billion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion digits. > > (American billion and trillion, 10**9 and 10**12 respectively.) What's that in crore? -- http://mail.python.org/mailman/listinfo/python-list
