In article <[email protected]>, Steven D'Aprano <[email protected]> wrote:
> For what it's worth, that last intermediate result (two to the power of > the 489-digit number) has approximately a billion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion trillion trillion > trillion trillion trillion trillion trillion trillion digits. > > (American billion and trillion, 10**9 and 10**12 respectively.) What's that in crore? -- http://mail.python.org/mailman/listinfo/python-list
