On Sunday, March 31, 2013 12:20:25 PM UTC-4, zipher wrote:
> Every line is now an element in list d. The question I have now is how can I
> make a dictionary out of the list d with the car manufacturer as the key and
> a tuple containing the year and the model should be the key's value. Here is
> a sample of what list d looks like:
>
>
>
>
> ['1899 Horsey Horseless', '1909 Ford Model T', '1911 Overland OctoAuto',
> '2003 Hummer H2', '2004 Chevy SSR']
>
>
>
> Any help would be appreciated!
>
>
>
>
> As long as your data is consistently ordered, just use list indexing. d[2]
> is your key, and (d[1],d[3]) the key's value.
>
>
>
> Mark
> Tacoma, Washington
Thank you, Mark! My problem is the data isn't consistently ordered. I can use
slicing and indexing to put the year into a tuple, but because a car
manufacturer could have two names (ie, Aston Martin) or a car model could have
two names(ie, Iron Duke), its harder to use slicing and indexing for those two.
I've added the following, but the output is still not what I need it to be.
t={}
for i in d :
t[d[d.index(i)][5:]]= tuple(d[d.index(i)][:4])
print (t)
The output looks something like this:
{'Ford Model T': ('1', '9', '0', '9'), 'Mosler Consulier GTP': ('1', '9', '8',
'5'), 'Scripps-Booth Bi-Autogo': ('1', '9', '1', '3'), 'Morgan Plus 8 Propane':
('1', '9', '7', '5'), 'Fiat Multipla': ('1', '9', '9', '8'), 'Ford Pinto':
('1', '9', '7', '1'), 'Triumph Stag': ('1', '9', '7', '0'), 'BMW 7-series':
('2', '0', '0', '2')}
Here the key is the car manufacturer and car model and the value is a tuple
containing the year separated by a comma.( Not sure why that is ?)
--
http://mail.python.org/mailman/listinfo/python-list
