Noah wrote:
> def unzip(list):
> if len(list) == 0: return ()
> l = []
> for t in range(len(list[0])):
> l.append(map( lambda x,t=t: x[t], list ))
> return tuple(l)
The simplest solution to this problem that I know of:
def unzip(iterable):
return zip(*iterable)
However, Guido feels that this is an abuse of the argument passing
machinery. For a version that is a little more careful in the case of
iterables, see:
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/302325
STeVe
--
http://mail.python.org/mailman/listinfo/python-list
