On Sat, May 4, 2013 at 12:13 PM, Pedro <pe...@ncf.ca> wrote: > First - this code constantly loops around an open socket. Is there a way to > use something like an interrupt so I don't have to loop constantly to monitor > the socket?
The accept() call should block. It's not going to spin or anything. If you need to monitor multiple sockets, have a look at select(). > Second, if any part of the program fails execution (crashes) the port often > remains open on my windows machine and the only way to close it that i know > of is through task manager or by rebooting the machine. Is there an easy way > around this problem ? If I don't close the port the program can't open it > again and crashes. It remains for a short time to ensure that there's no lurking connections. You can bypass this check by setting the SO_REUSEADDR option - lemme hunt that down in the Python docs, haven't done that in Python for a while... http://docs.python.org/3.3/library/socket.html#socket.socket.setsockopt s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) That should do the job. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
