On 05/16/2013 11:15 AM, Chris Angelico wrote:
On Fri, May 17, 2013 at 1:00 AM, loial <jldunn2...@gmail.com> wrote:
I want to split a string so that I always return everything BEFORE the LAST
underscore
HELLO_xxxxxxxx.lst # should return HELLO
HELLO_GOODBYE_xxxxxxxx.ls # should return HELLO_GOODBYE
I have tried with rsplit but cannot get it to work.
Any help appreciated
Try with a limit:
"HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)
['HELLO_GOODBYE', 'xxxxxxxx.ls']
"HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)[0]
'HELLO_GOODBYE'
You can easily get docs on it:
help("".rsplit)
Help on built-in function rsplit:
rsplit(...)
S.rsplit(sep=None, maxsplit=-1) -> list of strings
Return a list of the words in S, using sep as the
delimiter string, starting at the end of the string and
working to the front. If maxsplit is given, at most maxsplit
splits are done. If sep is not specified, any whitespace string
is a separator.
ChrisA
Now that you've all done his homework for him, see if The OP can spot
the one case where that won't work. It's easy to test for, but still
important to get right (for some definition of right).
--
DaveA
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