Funny! I made a lot of assumptions regarding your requirements specification. Let me know if it isn't what you need:
### 1strow_average.py ### #Assuming you have CSV (comma separated values) files such as: #1.txt = '0,1,2,3,4,5,6,7,8,9\n' \ # '10,11,12,13,14,15,16,17,18,19\n' \ # '20,21,22,23,24,25,26,27,28,29\n' ... # # Usage: contents[file][row][column] # contents[0] : file '1.txt' # contents[1][2] : 3rd row of file '2.txt' # contents[3][4][5] : 6th column of 5th row of file '4.txt' # len(contents) : quantity of files # len(contents[4]) : quantity of lines in file '5.txt' # len(contents[4][0]: quantity of values in the 1st line of file '5.txt' filenames = ['1.txt', '2.txt', '3.txt', '4.txt', '5.txt'] contents = [[[int(z) for z in y.split(',')] for y in open(x).read().split()] for x in filenames] s1c = [sum([r[0] for r in f]) for f in contents] a1r = [sum(f[0])/float(len(f[0])) for f in contents] print '\n'.join([x for x in ['File "{}" has 1st row average = {:.2f}'.format(n,a1r[i]) if s1c[i]==50 else '' for i,n in enumerate(filenames)] if x]) ________________________________ > From: wilke...@gmail.com > Date: Thu, 23 May 2013 01:13:19 +0900 > Subject: file I/O and arithmetic calculation > To: python-list@python.org > > > Dear all, > > I would appreciate if someone could write a simple python code for the > purpose below: > > I have five text files each of 10 columns by 10 rows as follows: > > > > file_one = 'C:/test/1.txt' > file_two = 'C:/test/2.txt' > . . . > file_five = 'C:/test/5.txt' > > I want to calculate the mean of first row (10 elements) for each file > (5 files), if mean of first column (10 elements) of each file (5 > files) is 50. > > Thank you in advance. > > Keira > > > -- http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list