Thanks
On Mon, May 27, 2013 at 4:19 PM, Denis McMahon <denismfmcma...@gmail.com>wrote: > On Mon, 27 May 2013 02:27:59 -0700, Avnesh Shakya wrote: > > > I want to create a new python file like 'data0.0.5', but if it is > > already exist then it should create 'data0.0.6', if it's also exist > > then next like 'data0.0.7'. I have done, but with range, please give > > me suggestion so that I can do it with specifying range. > > Try and put your description into the sequence of instructions you want > the computer follow. > > For this problem, my sequence of instructions would be: > > 1) Find the highest numbered existing file that matches the filename > data0.0.[number] > > 2) Create a new file that is one number higher. > > Now the solution is easy. Find the list of filenames in the directory > that match a suitable regular expression, take the numeric value of a > substring of the filename for each file and find the highest, add one to > it, then create the new file name. > > Something like the following (untested) with the relevant imports etc: > > nfn="data0.0."+str(max([int(f[8:])for f in os.listdir(p)if re.match > ('^data0.0.[0-9]+$',f)])+1) > > -- > Denis McMahon, denismfmcma...@gmail.com > -- > http://mail.python.org/mailman/listinfo/python-list >
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