That doesn't even works because input() is the same as eval(raw_input()). So
you'll get a NameError exception.
I think you know that. Perhaps you mean raw_input() instead of input().
In that case the answer is yes, it can be more 'efficient' because the
if-then-else clause always breaks the while loop.
I think you are looking for is a switch statement, which Python don't have.
You can use the following structure to emulate a switch statement:
def function1():
if raw_input() in option1:
print('he tumbles over you')
else:
print('he stabs you')
def function2():
if raw_input() in option2:
print('you trip him up')
else:
print('he stabs you')
def default():
print 'DEFAULT'
switch = {
option1: function1,
option2: function2
}
switch.get(randomizer, default)()
Note that switch is a dictionary and you can use it without creating a
variable, for example:
{ option1: function1,
option2: function2
}.get(randomizer, default)()
> Date: Mon, 3 Jun 2013 20:39:28 -0700
> Subject: Beginner question
> From: [email protected]
> To: [email protected]
>
> Is there a more efficient way of doing this? Any help is gratly appreciated.
>
>
> import random
> def partdeux():
> print('''A man lunges at you with a knife!
> Do you DUCK or PARRY?''')
> option1=('duck')
> option2=('parry')
> optionsindex=[option1, option2]
> randomizer=random.choice(optionsindex)
> while randomizer==option1:
> if input() in option1:
> print('he tumbles over you')
> break
> else:
> print('he stabs you')
> break
> while randomizer==option2:
> if input() in option2:
> print('you trip him up')
> break
> else:
> print('he stabs you')
> break
> partdeux()
> --
> http://mail.python.org/mailman/listinfo/python-list
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