Am 10.06.2013 15:37, schrieb Νικόλαος Κούρας:
Τη Δευτέρα, 10 Ιουνίου 2013 4:14:33 μ.μ. UTC+3, ο χρήστης Ulrich Eckhardt
έγραψε:
Am 10.06.2013 12:57, schrieb Νικόλαος Κούρας:
Τη Δευτέρα, 10 Ιουνίου 2013 12:40:01 μ.μ. UTC+3, ο χρήστης Ulrich
Eckhardt έγραψε:
for key in sorted( months.keys() ):
print('''
<option value="%s"> %s </option>
''' % (months[key], key) )
this in fact works, it sorts the dict by its keys()
No, it does not sort the dict. Please slow down, relax and take a look
at the documentation of sorted(). You are jumping to conclusions based
on flawed expectations and assumptions, which can only yield garbage in
the end.
it doe ssort the dict at least for keys() why not for values() too?
Well, because it does not sort the dict, it sorts the sequence that you
pass into sorted(). The dictionary that you retrieved from is not
modified. Which part of the documentation is unclear to you? Did you
even bother reading the docs?
for key in sorted( months.keys() ):
print('''
<option value="%s"> %s </option>
''' % (months[key], key) )
this in fact works, it sorts the dict by its keys() was mistaken before
but the sorting aint correct because its done alphabetically and not by
integer value.
Listen: Computers will always do what you tell them to. If you tell them
garbage, they will do garbage. If that is not what you want them to do,
it's your own fault. That means that you have to precisely(!!!) describe
what you want when talking to a computer. The computer will not try to
guess what you might have wanted.
Now, the above claim, that "it sorts the dict by its keys()" is simply
wrong. Instead, it outputs the dictionary's elements sorted by their
key. There is a fine distinction between the two. I know what you mean,
because I'm a human being and I can copy with your vague description,
but the computer doesn't.
Good luck, I'm outta here....
Uli
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