Why is there no builtin to consume a generator? I find that odd. On Wed, Jun 12, 2013 at 5:28 PM, Serhiy Storchaka <storch...@gmail.com> wrote: > 12.06.13 09:32, Phil Connell написав(ла): >> >> On 12 Jun 2013 01:36, "Roy Smith" <r...@panix.com <mailto:r...@panix.com>> >> >> wrote: >> > Well, continuing down this somewhat bizarre path: >> > >> > new_songs, old_songs = [], [] >> > itertools.takewhile( >> > lambda x: True, >> > (new_songs if s.is_new() else old_songs).append(s) for s in songs) >> > ) >> > >> > I'm not sure I got the syntax exactly right, but the idea is anything >> > that will iterate over a generator expression. That at least gets rid >> > of the memory requirement to hold the throw-away list :-) >> >> You could equivalently pass the generator to deque() with maxlen=0 - >> this consumes the iterator with constant memory usage. > > > any((new_songs if s.is_new() else old_songs).append(s) for s in songs) > > > -- > http://mail.python.org/mailman/listinfo/python-list
-- Fábio Santos -- http://mail.python.org/mailman/listinfo/python-list
