On 14/6/2013 4:14 πμ, Steven D'Aprano wrote:
On Thu, 13 Jun 2013 17:26:18 +0300, Νικόλαος Κούρας wrote:
i just want 4 cases to examine so correct execute to be run:
i'm reading and reading and reading this all over:
if '-' not in ( name and month and year ):
and i cant comprehend it.
Don't just read it. Open the interactive interpreter and test it.
name = "abcd"
month = "efgh"
year = "ijkl"
print(name and month and year)
If you run that, you will see what the result of
(name and month and year) is. Now, ask yourself:
"k" in (name and month and year)
True or false? Check your answer:
print("k" in (name and month and year))
>>> name="abcd"
>>> month="efgh"
>>> year="ijkl"
>>> print(name or month or year)
abcd
Can understand that, it takes the first string out of the 3 strings that
has a truthy value.
>>> print("k" in (name and month and year))
True
No clue. since the expression in parenthesis returns 'abcd' how can 'k'
contained within 'abcd' ?
>>> print(name and month and year)
ijkl
Seems here is returning the last string out of 3 strings, but have no
clue why Python doing this.
>>> print("k" in (name and month and year))
True
>>>
yes, since expression returns 'ijkl', then the in operator can detect
the 'k' character within the returned string.
--
What is now proved was at first only imagined!
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