On Mon, Jul 15, 2013 at 3:10 AM, Joseph L. Casale
<jcas...@activenetwerx.com> wrote:
> I have a dict of lists. I need to create a list of 2 tuples, where each tuple
> is a key from
> the dict with one of the keys list items.
>
> my_dict = {
> 'key_a': ['val_a', 'val_b'],
> 'key_b': ['val_c'],
> 'key_c': []
> }
> [(k, x) for k, v in my_dict.items() for x in v]
>
> This works, but I need to test for an empty v like the last key, and create
> one tuple ('key_c', None).
> Anyone know the trick to reorganize this to accept the test for an empty v
> and add the else?
Yeah, it's remarkably easy too! Try this:
[(k, x) for k, v in my_dict.items() for x in v or [None]]
An empty list counts as false, so the 'or' will then take the second
option, and iterate over the one-item list with None in it.
Have fun!
ChrisA
--
http://mail.python.org/mailman/listinfo/python-list
