On Friday, August 2, 2013 6:42:30 PM UTC-7, Terry Reedy wrote:
> Nonsense: they are executed just as you ask, even though what you ask is
>
> not what you meant.
>
>
>
> On 8/2/2013 8:40 PM, kevin4f...@gmail.com wrote:
>
>
>
> > def player_0_hitman(hit):
>
> > for card in pHands[target_player]:
>
> > if target_card[0] == card[0]:
>
> > count = pHands[target_player].count(card)
>
> > pHands[0].append(card)
>
> > pHands[target_player].remove(card)
>
> > ShowMessage("HIT: " + str(count) + " card(s) transferred")
>
> > else:
>
> else: # indent to match if
>
> > if target_card[0] != card[0]:
>
> # delete this if line, see below.
>
>
>
> > top_card = GetTopCard(sDeck)
>
> > pHands[0].append(top_card)
>
> > if top_card[0] == target_card[0]:
>
> > ShowMessage("HIT: LUCKILY Player 0 has fished up a rank <"
> > + str(top_card[0]) + ">!!!")
>
> > else:
>
> > ShowMessage("MISS: You fished up the rank <" +
> > str(top_card[0]) + ">")
>
> > hit = hit - 1
>
> > return hit
>
>
>
> This executes the for loop multiple times and the the else: clause of
>
> the *for* statement (see the ref manual). I believe you want the whole
>
> else: clause indented so that it will be executed when the if condition
>
> is false. If so, the second if is redundant and should just be removed.
>
> Yeah, thanks for the advice. But unfortunately, I already tried that and I
> ended up with a whole bunch of new errors.
>
> --
>
> Terry Jan Reedy
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