2013/9/20 Jugurtha Hadjar <jugurtha.had...@gmail.com>: > Hello, > # I posted this on the tutor list, but my message wasn't displayed > I shared some assembly code (microcontrollers) and I had a comment wit my > e-mail address for contact purposes. > Supposing my name is John Doe and the e-mail is john....@hotmail.com, my > e-mail was written like this: > removemejohn.dospames...@removemehotmail.com' > With a note saying to remove the capital letters. > Now, I wrote this : > for character in my_string: > ... if (character == character.upper()) and (character !='@') and > (character != '.'): > ... my_string = my_string.replace(character,'') > And the end result was john....@hotmail.com. > Is there a better way to do that ? Without using regular expressions (Looked > *really* ugly and it doesn't really make sense, unlike the few lines I've > written, which are obvious even to a beginner like me). > I obviously don't like SPAM, but I just thought "If I were a spammer, how > would I go about it". > Eventually, some algorithm of detecting the john<dot>doe<at>hotmail<dot>com > must exist. > retrieve the original e-mail address? Maybe a function with no inverse > function ? Generating an image that can't be converted back to text, etc.. > If this is off-topic, you can just answer the "what is a better way to do > that" part. > > Thanks, > -- > ~Jugurtha Hadjar, > -- > https://mail.python.org/mailman/listinfo/python-list
Hi, is the regex really that bad for such simple replacement? >>> re.sub(r"[A-Z]", "", "removemejohn.dospames...@removemehotmail.com") 'john....@hotmail.com' Alternatively, you can use a check with the string method isupper(): >>> "".join(char for char in "removemejohn.dospames...@removemehotmail.com" if >>> not char.isupper()) 'john....@hotmail.com' or using a special form of str.translate() >>> "removemejohn.dospames...@removemehotmail.com".translate(None, >>> "ABCDEFGHIJKLMNOPQRSTUVWXYZ") 'john....@hotmail.com' which is the same like: >>> import string >>> "removemejohn.dospames...@removemehotmail.com".translate(None, >>> string.ascii_uppercase) 'john....@hotmail.com' Another possibility would be to utilise ord(...) >>> "".join(char for char in "removemejohn.dospames...@removemehotmail.com" if >>> ord(char) not in range(65, 91)) 'john....@hotmail.com' >>> Well, maybe there are other possibilities, these above are listed roughly in the order of my personal preference. Of course, others may differ... hth, vbr -- https://mail.python.org/mailman/listinfo/python-list
