On Saturday, October 12, 2013 10:20:24 AM UTC+1, Peter Otten wrote: > reubennott...@gmail.com wrote: > > > > > I've been working on a program and have had to halt it due a slight > > > problem. Here's a basic version of the code: > > > > > > a = 'filled' > > > b = 'filled' > > > c = 'empty' > > > d = 'empty' > > > e = 'filled' > > > f = 'empty' > > > g = 'filled' > > > > > > testdict = {a : 'apple' , b : 'banana' , c : 'cake' , d : 'damson' , e : > > > 'eggs' , f : 'fish' , g : 'glue'} > > > > You have duplicate keys here, which becomes obvious when you spell out the > > values > > > > testdict = {"filled": "apple", "filled": "banana", ...} > > > > When you do that, the last value ("banana") wins, all others (e. g. "apple") > > are dropped. > > > > > Now what I want to do, is if a variable is filled, print it out. This > > > however isn't working how I planned. The following doesn't work. > > > > > > for fillempt in testdict: > > > if fillempt == 'filled': > > > print(testdict[fillempt]) > > > > > > All this does though, is print glue, where I'd want it to print: > > > > > > apple > > > banana > > > eggs > > > glue > > > > > > Perhaps a dictionary isn't the best way to do this.. I wonder what else I > > > can do... > > > > A dictionary is spot-on, but you have to use the unique "apple", > > "banana",... as keys: > > > > >>> status = {"apple": "filled", "banana": "filled", "cake": "empty"} > > >>> for item in status: > > ... if status[item] == "filled": > > ... print(item) > > ... > > apple > > banana > > > > Could it be that you just confused dict keys with dict values?
This fixed it, thank you! I did think a dictionary was right; I never considered swapping the keys with the values, though. A simple 'fix, but it worked. You've been a great help. -- https://mail.python.org/mailman/listinfo/python-list