Why does the numpy masked_where create a special case for all False? import numpy x = numpy.array([[9,9,9,9,9,9],[9,9,9,9,9,9],[9,9,9,9,9,9],[9,9,9,9,9,9]]) y = numpy.ma.masked_where(x<3,x) y.mask Out[1]: False z= numpy.arange(20) z.reshape(4,5) Out[1]: array([[ 0, 1, 2, 3, 4], [ 5, 6, 7, 8, 9], [10, 11, 12, 13, 14], [15, 16, 17, 18, 19]]) y = numpy.ma.masked_where(z<3,z) y.mask Out[1]: array([ True, True, True, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False], dtype=bool)
Is there a good way to work around this and get an all False array? Thanks -- https://mail.python.org/mailman/listinfo/python-list