On 10/26/2013 07:23 PM, Peter Cacioppi wrote:
Am I the only one who finds this function super useful?def _code_file() : return os.path.abspath(inspect.getsourcefile(_code_file)) I've got one in every script. It's the only one I have to copy around. For my workflow ... so handy. I've got os.path.dirname aliased to dn, so its dn(_code_file()) that I find myself reaching for fairly often...
Huh? In what kind of a workflow are you running a python file without knowing *what* file you are runnung?
Or am I just misinterpreting what this code does? Confused but curious, Gary Herron -- https://mail.python.org/mailman/listinfo/python-list
