On 11/11/2013 7:02 AM, sg...@hotmail.co.uk wrote:
(Sorry for posting through GG, I'm at work.)
On Monday, November 11, 2013 11:25:42 AM UTC, Steven D'Aprano wrote:
Suppose I have a function that needs access to globals:
# module A.py
def spam():
g = globals() # this gets globals from A
introspect(g)
As written, spam() only sees its own globals, i.e. those of the module in
which spam is defined. But I want spam to see the globals of the caller.
# module B
import A
A.spam() # I want spam to see globals from B
I can have the caller explicitly pass the globals itself:
def spam(globs=None):
if globs is None:
globs = globals()
introspect(globs)
But since spam is supposed to introspect as much information as possible,
I don't really want to do that. What (if anything) are my other options?
How about this?
# module A.py
import inspect
def spam():
return inspect.stack()[1][0].f_globals
In Python 3, the attribute is __globals__. In either case, it is only
defined on Python coded functions, so one should be prepared for it to
not exist. That possibility is real because there *are* builtins like
map and filter that take function args and call them.
Inspect has been modified in Py 3, but stack is still there.
# module B.py
import A
print(A.spam() is globals()) # prints True
def f():
return A.spam()
# module C.py
import B
print(B.f() is vars(B)) # prints True
I don't really know what I'm doing but I guess it won't work in alternative
implementations of Python.
--
Terry Jan Reedy
--
https://mail.python.org/mailman/listinfo/python-list
