On 21 November 2013 06:46, John O'Hagan <resea...@johnohagan.com> wrote:
>
> I found a verbal description of such an algorithm and came up with
> this:
>
> def multicombs(it, r):
> result = it[:r]
> yield result
> while 1:
> for i in range(-1, -r - 1, -1):
> rep = result[i]
> if rep < it[i]:
> break
> else:
> break
> for j, n in enumerate(it):
> if n > rep:
> break
> result = result[:i] + it[j:j - i]
> yield result
I'm not really sure what it is you're asking for. I thought if I ran
the code I'd understand but that just confused me more. Is the output
below correct? If not what should it be?
multicombs("abracadabra", 0)
['']
multicombs("abracadabra", 1)
['a']
multicombs("abracadabra", 2)
['ab', 'br', 'ra']
multicombs("abracadabra", 3)
['abr', 'ara', 'bra']
multicombs("abracadabra", 4)
['abra']
multicombs("abracadabra", 5)
['abrac', 'abrbr', 'abrra', 'braca', 'brara', 'brbra', 'racad',
'racbr', 'racra']
Oscar
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