On Monday, 16 December 2013 13:10:22 UTC+8, Gary Herron wrote: > On 12/15/2013 08:38 PM, [email protected] wrote: > > > Hi guys, I am trying to create a fixed list which would allow my values to > > be wrapped around it. > > > For example i have 10 values : 0,1,2,3,4,5,6,7,8,9 > > > I need to create a list which contains 4 numbers and when the number > > exceeds the list, it would overwrite the first value. > > > [0,1,2,3] > > > [4,1,2,3] > > > [5,4,1,2] > > > > > > Thanks in advance and much help appreciated. > > > > Is the output really three lists as you show. Or is that one list whose > > contents you have shown three snapshots of? Then what was the point of > > putting 4 in the first spot when you are just going to move it to the > > second spot? And why stop at 4 and 5? What about 7, 8, and 9? > > > > Are you really shifting elements onto the beginning of the list and off > > the end of the list? (That's easy to do, but is that what you want?) > > > > If I follow your example a few elements further I get [9,8,7,6], just > > the last four elements of the original list in reverse order -- so there > > is no need fill a list and "wrap-around" -- just grab the last four > > elements and reverse them. > > > > Or have I misunderstood the problem completely? (I think that's > > likely.) I'm sure Python is general enough to do what you want, but > > you'll have to do a much better job telling is what you want. While you > > are at it, tell us what you've already done, and how it fails to do > > whatever it is you want. > > > > Gary Herron
The idea is to grab the last 4 elements of the array. However i have an array that contains a few hundred elements in it. And the values continues to .append over time. How would i be able to display the last 4 elements of the array under such a condition? -- https://mail.python.org/mailman/listinfo/python-list
