On Tue, Dec 17, 2013 at 4:41 AM, Ravi Prabakaran <ravi....@gmail.com> wrote: >> Hi Chris, > > Thanks for reply. If you have any good idea with loop, please post. But > i'm looking same without loop because python has slicing,concatenating and > other straight forward feature. I guess it can be done without loop. My > client does not prefer loops and expects simple and neat code to improve > performance. We are dealing with billion data.
I'm going to hope that it was in error that you sent this off-list, or at least that you won't mind my replying on-list. Here's one way to do it: t = ['Start','End'] a = [[1,2,3,4], [5,6,7,8]] result = [] for cur in a: result.append("%s - %d"%(t[0],cur[2])) result.append("%s - %d"%(t[1],cur[3])) ChrisA -- https://mail.python.org/mailman/listinfo/python-list