On Mon, Jan 20, 2014 at 9:44 PM, km <srikrishnamo...@gmail.com> wrote:
>>>> p = re.compile('(CAA)+?(TCT)+?(TA)+?')
>>>> p.findall('CAACAACAATCTTCTTCTTCTTATATA')
> [('CAA', 'TCT', 'TA')]
>
> But I instead find only one instance of the CAA/TCT/TA in that order.
> How can I get 3 matches of CAA, followed by four matches of TCT followed by
> 2 matches of TA ?
> Well these patterns (CAA/TCT/TA) can occur any number of times and atleast
> once so I have to use + in the regex.
You're capturing the single instance, not the repeated one. It is
matching against all three CAA units, but capturing just the first.
Try this:
>>> p = re.compile('((?:CAA)+)((?:TCT)+)((?:TA)+)')
>>> p.findall('CAACAACAATCTTCTTCTTCTTATATA')
[('CAACAACAA', 'TCTTCTTCTTCT', 'TATATA')]
This groups "CAA" with non-capturing parentheses (?:regex) and then
captures that with the + around it.
ChrisA
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