On 2014-01-22 17:58, Larry Martell wrote:
> I have the need to check for a files existence against a string,
> but I need to do case-insensitively. I cannot efficiently get the
> name of every file in the dir and compare each with my string using
> lower(), as I have 100's of strings to check for, each in a
> different dir, and each dir can have 100's of files in it. Does
> anyone know of an efficient way to do this? There's no switch for
> os.path that makes exists() check case-insensitively is there?
Is it possible to rephrase the problem in terms of a different
algorithm that can be made case-insensitive? Something like
from_db = set(
row[0].upper()
for row in db.execute(
"select filename from tblfoo where ..."
).fetchall()
)
from_fs = dict(
(fname.upper(), os.path.join(pth, fname))
for pth, dirs, files in os.walk(ROOT)
for fname in files
)
common_filenames = from_db & set(from_fs)
for fname in common_filenames:
print from_fs[fname]
-tkc
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