Hello,
On Sat, Jan 25, 2014 at 02:02:15AM -0800, justinpmull...@gmail.com wrote:
> My son is learning Python and I know nothing about computers.
:)
> He's written a simple calculator program that doesn't work. For the life of
> me, I can't see why.
> Any help gratefully received. Here's his code:
> def a():
> import sys
> print("welcome to the calculation")
> print("please type a number")
> one = int(sys.stdin.readline())
> print("type d for division,")
> print("type m for multiplication,")
> print("type s for subtraction,")
> print("and type p for plus")
> op = (sys.stdin.readline())
> print("%s selected" % op)
> print("please enter another number")
> two = int(sys.stdin.readline())
> if op == str(d):
> out == one / two
> print("the answer is %s" % out)
> elif op == "m":
> out == one * two
> print("the answer is %s" % out)
> elif op == "s":
> out == one - two
> print("the answer is %s" % out)
> elif op == "p":
> out == one + two
> print("the answer is %s" % out)
> else:
> print("huh")
>
> Where is he going wrong?
what's your error message?
First, you have to put an interpreter in first line - if you're
on Linux/Unix:
#!/usr/bin/python
or some kind of that. I don't know what's the expected on Windows
:(.
Second, you defined a funcfion, called "a", and if you want to
see how does it work, you must call that (after you define it):
def a():
...
...
a()
Third, at the first statement (if op == str(d)) you're
referencing for an undefined variable (d), I think you would
put `if op == "d":', instad of that.
Good luck,
Ervin
--
I � UTF-8
--
https://mail.python.org/mailman/listinfo/python-list
