I ran across this and I thought there must be a better way of doing it, but then after further consideration I wasn't so sure.
if key[:1] + key[-1:] == '<>': ...
Some possibilities that occurred to me:
if key.startswith('<') and key.endswith('>'): ...
and:
if (key[:1], key[-1:]) == ('<', '>'): ...
I haven't run these through a profiler yet, but it seems like the original
might be the fastest after all?
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