In article <[email protected]>,
Terry Reedy <[email protected]> wrote:
> On 2/18/2014 11:47 AM, Chris Angelico wrote:
> > I call this "Russian Exception Roulette". It came about because of
> > some discussions on python-ideas regarding the new PEP 463 and
> > exception handling.
> >
> > try:
> > exc = getattr(__builtins__,random.choice(list(filter(lambda x:
> > x.endswith("Error"),dir(__builtins__)))))
> > f()
> > except exc:
> > print("You win!")
> >
> > Given a function f(), defined elsewhere, what will this do?
>
> I am not sure what you are asking or what your point is. If f happens to
> raise the randomly selected exception, it prints 'You win!', otherwise
> it does nothing.
def f():
print("You win!")
problem solved :-)
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