[rbt]
> What is the appropriate way to break out of this while loop if the for
> loop finds a match?
>
> while 1:
> for x in xrange(len(group)):
> try:
> mix = random.sample(group, x)
> make_string = ''.join(mix)
> n = md5.new(make_string)
> match = n.hexdigest()
> if match == target:
> print "Collision!!!"
> print make_string
> Stop = time.strftime("%H:%M:%S-%m-%d-%y", time.localtime())
> print "Stop", Stop
> break
> else:
> continue
> except Exception, e:
> print e
I would wrap the whole thing in a function definition. When you find a
match, just return from the function. Besides cleanly exiting from
multiple loops, the function approach usually leads to better factoring
(in this case, segregating the search logic from everything else).
Raymond
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