rbt wrote: > Say I have a list that has 3 letters in it: > > ['a', 'b', 'c'] > > I want to print all the possible 4 digit combinations of those 3 > letters:
When I have occasion to do an iteration of iterations, I either use recursion (already posted) or use an accumulator type loop: items = ['a','b','c'] accume = [[],] for pos in range(4): old_accume, accume = accume, [] for comb in old_accume: for item in items: accume.append(comb + [item]) accume = [''.join(x) for x in accume] print accume ['aaaa', 'aaab', 'aaac', 'aaba', 'aabb', 'aabc', 'aaca', 'aacb', 'aacc', 'abaa', 'abab', 'abac', 'abba', 'abbb', 'abbc', 'abca', 'abcb', 'abcc', 'acaa', 'acab', 'acac', 'acba', 'acbb', 'acbc', 'acca', 'accb', 'accc', 'baaa', 'baab', 'baac', 'baba', 'babb', 'babc', 'baca', 'bacb', 'bacc', 'bbaa', 'bbab', 'bbac', 'bbba', 'bbbb', 'bbbc', 'bbca', 'bbcb', 'bbcc', 'bcaa', 'bcab', 'bcac', 'bcba', 'bcbb', 'bcbc', 'bcca', 'bccb', 'bccc', 'caaa', 'caab', 'caac', 'caba', 'cabb', 'cabc', 'caca', 'cacb', 'cacc', 'cbaa', 'cbab', 'cbac', 'cbba', 'cbbb', 'cbbc', 'cbca', 'cbcb', 'cbcc', 'ccaa', 'ccab', 'ccac', 'ccba', 'ccbb', 'ccbc', 'ccca', 'cccb', 'cccc'] Optimize as you see fit. -- http://mail.python.org/mailman/listinfo/python-list