On 4/28/14 12:00 PM, Roy Smith wrote:
Fundamentally, these numbers have between 0 and 4 decimal digits of precision,
and I want to be able to intuit how many each has, ignoring the obvious
floating point roundoff problems. Thus, I want to map:
38.0 ==> 0
41.2586 ==> 4
40.75280000000001 ==> 4
49.25 ==> 2
33.795199999999994 ==> 4
36.837199999999996 ==> 4
34.1489 ==> 4
45.5 ==> 1
Is there any clean way to do that? The best I've come up with so far is to
str() them and parse the remaining string to see how many digits it put after
the decimal point.
That sounds like a pretty clean way: len(str(num).partition(".")[2]),
though it also sounds like you understand all of the inaccuracies in
that technique.
--
Ned Batchelder, http://nedbatchelder.com
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