On 6/18/14, 4:03 PM, cutey Love wrote:
I'm trying to write data to a text file
But I'm getting the error:
TypeError: invalid file: <_io.TextIOWrapper
Always better to err on posting too much context (the entire traceback)
than too little.
Code is
def saveFile():
file_path = filedialog.asksaveasfile(mode='w', filetypes=[('text files', '.txt')],
defaultextension=".txt")
fo = open(file_path, 'w')
I used Google (searched on "filedialog.asksaveasfile") to realize that
you are likely using Tkinter. I then used Google to find out the API for
filedialog.asksaveasfile() and I found that it returns the ALREADY OPEN
FILE for you to write to, not the name of the file you are writing to.
Referring to that same documentation, I see there's another function you
are probably more interested in: filedialog.asksaveasfilename(). Then,
you can open the file, write to it, and close it and be in control of
every step. Not sure which is preferable, though, as I have no (recent)
Tkinter experience.
for e in myList:
fo.write(e)
fo.close()
You should use a context manager to open, write to, and close files.
Such as:
with open(file_path, 'w') as fo:
for e in myList:
fo.write(e)
The file is being created if not already present but no data is written
filedialog.asksaveasfile() was opening it for you. It was being closed
automatically when file_path fell out of scope (after the exception
caused by your fo = open(file_path, 'w') line.
My response was intended to help.
Paul
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