On 8/25/2014 4:14 PM, Seymore4Head wrote:
import random
sets=3
for x in range(0, sets):
pb2=random.choice([1-53])
You want random.randint(1, 53)
...
alist = sorted([pb1, pb2, pb3, pb4, pb5])
print ("Your numbers: {} Powerball: {}".format(alist, pb6))
I am trying this example. The program works, but the numbers don't
line up if the number of digits are different sizes.
http://openbookproject.net/pybiblio/practice/wilson/powerball.php
To get them to line up, you have to format each one to the same width.
Suggestion please?
BTW the exercise instructions say to use the choice function.
import random
sets=3
def ran53():
return random.randint(1, 53)
f1 = '{:2d}'
bform = "Your numbers: [{0}, {0}, {0}, {0}, {0}]".format(f1)
pform = " Powerball: {0}".format(f1)
for x in range(0, sets):
balls = sorted(ran53() for i in range(5))
print(bform.format(*balls), pform.format(ran53()))
BTW the exercise instructions say to use the choice function.
I am not a fan of exercises that say to do something the wrong way, but
if you really had to,
n54 = [i for i in range(1, 54)]
random.choice(n54)
An alternative to choosing numbers is to choose from 2-char number strings.
n53 = ['%2d' % i for i in range(1, 54)]
But then you have to figure out how to avoid having 6 pairs of quotes in
the output ;=)
--
Terry Jan Reedy
--
https://mail.python.org/mailman/listinfo/python-list
