On 01/10/2014 23:37, Shiva wrote:
Hi,
I am learning Python (version 3.4) strings.I have a function that takes in a
parameter and prints it out as given below.
def donuts(count):
if count <= 5:
print('Number of donuts: ',count)
else:
print('Number of donuts: many')
return
It works fine if I call
donuts(5)
It returns:
we have 5 DN (as expected)
It doesn't :) As it takes the first path through the function it will
*print* 'Number of donuts: 5' and then return None as you haven't
specified what your function returns.
However if I do :
test(donuts(4), 'Number of donuts: 4')
where test is defined as below:
def test(got, expected):
print('got: ', got, 'Expected:' ,expected)
if got == expected:
prefix = ' OK '
else:
prefix = ' X '
print (('%s got: %s expected: %s') % (prefix, repr(got), repr(expected)))
Only 'None' gets passed on to parameter 'got' instead of the expected value
of 4.
Your expectations are wrong, your function makes no attempt to return
the value you've passed in. I'd (re)read the tutorial again and digest
it, then have another go.
Any idea why 'None' is getting passed even though calling the donuts(4)
alone returns the expected value?
What is your expected value? My expected value is None for a value of 4
as you've given a return statement without specifying a value.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
--
https://mail.python.org/mailman/listinfo/python-list
