On Mon, 06 Oct 2014 08:42:01 -0600, Michael Torrie <torr...@gmail.com> wrote: > On 10/06/2014 07:07 AM, varun...@gmail.com wrote: >>> Okay, I forgot to explain them. L is a set of links, dist is a >>> number (distance), bd is the bandwidth and hc is a number as well >>> (hopcount)...different bandwidths, hopcounts and distances for different >>> links... b(i,x) is what i intend to calculate out of these details...here >>> 'i'could be the head or tail of the link l and x is a node that hosts i >>> Thank You >> >> Unbelievable. I again forgot to express them >> L = [(1,3), (5,7), .....] >> bd = [23, 34,43.44.....] >> dist = [3,7,5,7, ....] >> hc = [2,3,4,1,2,2,...] >> for every l belonging to L, i could be either 1 or 3 for L[0], similarly >> for L[1] it could be 5 or 7 > > You might want to ask on the scipy mailing list[1]. I'm sure the folks > over there deal with complex sums and math all the time. Numpy > (standalone, or as part of scipy) has some facilities for working with > vectors, products, and summations in an efficient manner.
I don't think the OP is interested in complex numbers. I think this is a question about organizing loops. But I can't tell for sure. My guess is that l is one of the pairs in L, and that i is one of the elements in l, or perhaps both in succession. OP hints that "x is a node that hosts i", but how that affects the right-hand side of the equation defining the quantity to be computed, which is lost in the history of this thread, is unclear. There's a lesson here for the OP, varun7rs: If your initial query had been clear and complete, you would have your answer by now. -- To email me, substitute nowhere->runbox, invalid->com. -- https://mail.python.org/mailman/listinfo/python-list
