Is it possible to have a default dictionary where the default is dependant on the key?
I was hoping something like this might work: >>> m = defaultdict(lambda key: key+1) But it obviously doesn't: >>> m[3] Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: <lambda>() takes exactly 1 argument (0 given) -- Antoon Pardon -- https://mail.python.org/mailman/listinfo/python-list
