Le 18/11/2014 15:49, Juan Christian a écrit :
I was doing some tests, then I tried this:
app = QApplication(sys.argv)
MainWindow = loadui("main.ui")
MainWindow.btn.clicked.connect(MainWindow.txtbox.setText(test()))
MainWindow.show()
app.exec_()
But I get "RuntimeError: Failed to connect signal clicked().", why?
The syntax is correct, I don't know why it failed, the btn is in the
Form too, it's a QPushButton.
The test func is just a simple func that returns a random text.
On Tue Nov 18 2014 at 11:08:48 AM Juan Christian
<juan0christ...@gmail.com <mailto:juan0christ...@gmail.com>> wrote:
Many thanks, worked. The only problem now is that I don't have
auto-complete for anything, because of this approach... I'll have
to check the doc more regularly. ^^
....
https://mail.python.org/mailman/listinfo/python-list
You can't have a slot like this:
MainWindow.btn.clicked.connect(MainWindow.txtbox.setText(test()))
because that's mean: "connect to the return of
MainWindow.txtbox.setText(test())" and it's not possible at this stage
of your program.
Use instead a function:
MainWindow.btn.clicked.connect(my_slot) # No parenthesis !
def my_slot():
MainWindow.txtbox.setText(test())
--
https://mail.python.org/mailman/listinfo/python-list
