I had another attempt at inputting the code perhaps with the right indentation,
I still get an error return, but not one that indicates that the code has not
been read, as you suggested. re:-
----------------------------------------------------------------------------
Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> from bs4 import BeautifulSoup
>>> with open("ecologicalpyramid.html","r") as ecological_pyramid:
... soup = BeautifulSoup(ecological_pyramid,"lxml")
... producer_entries = soup.find("ul")
File "<stdin>", line 3
producer_entries = soup.find("ul")
^
SyntaxError: invalid syntax
>>> from bs4 import BeautifulSoup
File "<stdin>", line 1
from bs4 import BeautifulSoup
----------------------------------------------------------------------------
If, as you suggest I left a free line after the "with open( etc" line, console
returns an error, if I leave a free line after the "soup = etc" line which
comes after, again I get an error return, my only point is that with the above
input, console return does not seem to infer that soup has not been defined.
You recommend that I put all the code into a file then run it - how do I do
that ? I am new to Python, as you might have gathered.
Thank you for your help.
Yours Simon
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