I've made a snniferr for a ICMP socket that works with IPv4. This is the code:
import sys import socket import struct import select import time import signal import re HOST = raw_input("Enter the interface to listen: ") s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_ICMP) s.bind((HOST, 0)) s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1) print "Server Started......" for i in range(1,2000): data = s.recvfrom(65565) d1 = str(data[0]) data1 = re.search('@@(.*)', d1) command = data1.group(0) cmd = command[2:] if i%2 == 0: d = data[1] d1 = str(d) ip = d1[2:-5] print cmd print ip I have done a modification to adapt it to IPv6: s = socket.socket(socket.AF_INET6, socket.SOCK_RAW, socket.IPPROTO_ICMPV6) However I recive the next error: File "server.py", line 16, in <module> s.bind((HOST, 0)) File "/usr/lib/python2.7/socket.py", line 224, in meth return getattr(self._sock,name)(*args) socket.error: [Errno 22] Invalid argument Could someone please help me?. Thanks in advance -- View this message in context: http://python.6.x6.nabble.com/Socket-ICMP-V6-error-tp5083962.html Sent from the Python - python-list mailing list archive at Nabble.com. -- https://mail.python.org/mailman/listinfo/python-list