On Sat, Jan 24, 2015 at 11:55 AM, Chris Angelico <ros...@gmail.com> wrote:
> That's still only able to assign to a key of a dictionary, using the
> function name. There's no way to represent fully arbitrary assignment
> in Python - normally, you can assign to a name, an attribute, a
> subscripted item, etc. (Augmented assignment is a different beast
> altogether, and doesn't really make sense with functions.) There's no
> easy way to say "@stash(dispatch_table_a['asdf'])" and have that end
> up assigning to exactly that.
Obviously, nobody will be happy until you can do:
def call(*a, **kw): return lambda f: f(*a, **kw)
@call()
def x, y ():
yield 1
yield 2
Actually, maybe not even then.
-- Devin
--
https://mail.python.org/mailman/listinfo/python-list
