subhabrata.bane...@gmail.com writes:
> Dear Group,
>
> I am trying to open multiple files at one time.
> I am trying to do it as,
>
> for item in [ "one", "two", "three" ]:
> f = open (item + "world.txt", "w")
> f.close()
>
> This is fine. But I was looking if I do not know the number of
> text files I would create beforehand, so not trying xrange option
> also.
>
> And if in every run of the code if the name of the text files have
> to created on its own.
>
> Is there a solution for this?
I have trouble comprehending your question so I am going to guess a bit
– feel free to clarify your problem.
If you want to repeat a set of commands not for a certain number of
items but based on a condition take a look at the *while-loop*. The
basic loop construct looks like this:
while condition:
do_stuff()
Now the problem: *While* your program still has stuff to do (you have to
come up with an appropiate condition) you want to write output to files.
The filenames will be a concatenation of a number counting the already
created files and a predifined string (say "world.txt").
(Is this a correct description of your problem? Again: feel free to
clarify.)
The following lines might get you closer to a solution:
j = 1
continue_to_open_files = True
while continue_to_open_files:
with open("%03iworld" % j, "w") as f:
f.write("some content")
if some_condition:
continue_to_open_files = False
j += 1
Alternativly /itertools.count/ allows using of the for-loop:
import itertools
for j in itertools.count(1):
with open("%03iworld" % j, "w") as f:
f.write("some content")
if some_condition:
break
Translating numbers represented by digits into words is another problem.
--
Felix Dietrich
--
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