On Tue, May 5, 2015 at 3:23 PM, Ian Kelly <ian.g.ke...@gmail.com> wrote:
> On Tue, May 5, 2015 at 3:00 PM, Dave Angel <da...@davea.name> wrote:
>> def loop(func, funcname, arg):
>> start = time.time()
>> for i in range(repeats):
>> func(arg, True)
>> print("{0}({1}) took {2:7.4}".format(funcname, arg, time.time()-start))
>>
>> start = time.time()
>> for i in range(repeats):
>> func(arg)
>> print("{0}({1}) took {2:7.4}".format(funcname, arg, time.time()-start))
>
> Note that you're explicitly passing True in one case but leaving the
> default in the other. I don't know whether that might be responsible
> for the difference you're seeing.
I don't think that's the cause, but I do think that it has something
to do with the way the timing is being run. When I run your loop
function, I do observe the difference. If I reverse the order so that
the False case is tested first, I observe the opposite. That is, the
slower case is consistently the one that is timed *first* in the loop
function, regardless of which case that is.
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