On 10/05/2015 10:58, Steven D'Aprano wrote:
from timeit import Timer
def func():
a = 2
b = 3
c = 4
return (a+b)*(a-b)/(a*c + b*c)
code = func.__code__
assert func() == eval(code)
t1 = Timer("eval; func()", setup="from __main__ import func")
t2 = Timer("eval(code)", setup="from __main__ import code")
# Best of 10 trials.
print (min(t1.repeat(repeat=10)))
print (min(t2.repeat(repeat=10)))
Maybe the overheads of using eval() are significant when calling a
simple function such as your example.
When I made it do a bit more work:
def func():
a = 2
b = 3
c = 4
for i in range(50):
x=(a+b)*(a-b)/(a*c + b*c)
return (a+b)*(a-b)/(a*c + b*c)
Then the eval() call took only 3% longer rather than 100%.
--
Bartc
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