Hello friends:
I saw the following example at
http://nafiulis.me/potential-pythonic-pitfalls.html#using-mutable-default-arguments
and
did not believe the output produced and had to try it for myself....
def foo(a,b,c=[]):
c.append(a)
c.append(b)
print(c)
foo(1,1)
foo(1,1)
foo(1,1)
produces:
[1, 1]
[1, 1, 1, 1]
[1, 1, 1, 1, 1, 1]
One would expect the following output:
[1, 1]
[1, 1]
[1, 1]
Doesn't this valid the zen of python: "Explicit is better than implicit." ?
Thanks!
Billy
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