On Fri, 12 Jun 2015 04:12:52 -0700, Thomas Güttler wrote:
> Here is a snippet from the argparse module:
>
> {{{
> def parse_known_args(self, args=None, namespace=None):
> ...
> # default Namespace built from parser defaults if namespace is
> None:
> namespace = Namespace() # < ======= my issue
> }}}
>
> I subclass from the class of the above snippet.
>
> I would like to use a different Namespace class.
>
> if the above could would use
>
> namespace = self.Namespace()
>
> it would be very easy for me to inject a different Namespace class.
Yes it would.
And here is how you do it, even when the parent class doesn't:
class MySubclass(ParentClass):
Namespace = Namespace
def parse_known_args(self, args=None, namespace=None):
if namespace is None:
namespace = self.Namespace()
# any other method overriding needed
return super().parse_known_args(args, namespace)
In Python 2, you cannot use super(), you have to explicitly provide the
arguments:
return super(MySubclass,self).parse_known_args(args,namespace)
--
Steve
--
https://mail.python.org/mailman/listinfo/python-list
