On 6/20/2015 10:47 PM, Nasser M. Abbasi wrote:
I did manage to find a way:
---------------------------------
r1 =np.hstack([(v1,v2)]).T
r2 =np.hstack([(v3,v4)]).T
mat = np.vstack((r1,r2))
-----------------------------
Out[211]:
array([[ 1, 4],
[ 2, 5],
[ 3, 6],
[ 7, 10],
[ 8, 11],
[ 9, 12]])
But it is not as intuitive as with Matlab, where one can just write
-------------------------------
v1=[1,2,3]'; v2=[4,5,6]';
v3=[7,8,9]'; v4=[10,11,12]';
m=[v1 v2;v3 v4]
-------------------------------
Here is a way a little closer to Matlab's method: First
make all the vectors column vectors
v1=np.array([(1,2,3)]).T
v2=np.array([(4,5,6)]).T
v3=np.array([(7,8,9)]).T
v4=np.array([(10,11,12)]).T
mat =np.hstack(( np.vstack((v1,v3)), np.vstack((v2,v4))) )
Out[236]:
array([[ 1, 4],
[ 2, 5],
[ 3, 6],
[ 7, 10],
[ 8, 11],
[ 9, 12]])
There are way too many '(([[]]))' things in Python :)
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