On 17/08/2015 12:42, Владислав wrote:
# first: works fine

x = [1, 2, 4, 2, 1, 3]
x = list(set(x))
x.sort()
print(x) /# output: 1, 2, 3, 4

/# second: why x became None ??

x = [1, 2, 4, 2, 1, 3]
x = list(set(x)).sort()
print(x) /# output: None/

I know that sort() returns None, but I guess that it would be returned x
that was sorted. Why so?/

A set is created from x. This is converted to a list. You call sort() and assign the return value from that, None, to x. You will see exactly the same thing above if you do:-

x = x.sort()

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what you can do for our language.

Mark Lawrence

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