[EMAIL PROTECTED] wrote: > i have read > finding sublist > http://groups.google.it/group/comp.lang.python/browse_thread/thread/50b09a0aca285256/5156ada81fc9358a?hl=it#5156ada81fc9358a > > > the problem was in a string to find if we have two substring non > overlapping of lenght al least 4 > > it was done by > r=re.compile(r'(?P<seq>.{4,}).*(?P=seq)') > > my knowhow on re is null > there is a way in re for ask if a substring is the reverse of the > otherone? First seq is second seq in reverse order
For a fixed-length substring you can use brute force. Here is a regex that matches a string containing a four-character substring and its reverse: (?P<s1>.)(?P<s2>.)(?P<s3>.)(?P<s4>.).*(?P=s4)(?P=s3)(?P=s2)(?P=s1) You might want to look at the Regular Expression HOW-TO document: http://www.amk.ca/python/howto/regex/ Kent -- http://mail.python.org/mailman/listinfo/python-list
