That might also work: new_list = [i for i in the_list if i not in targets] # given you have no special requirements for the selection # out of 'targets'
-Sivan On Wed, Dec 9, 2015 at 12:58 AM, Thomas 'PointedEars' Lahn < pointede...@web.de> wrote: > Mark Lawrence wrote: > > > On 03/12/2015 01:15, c.bu...@posteo.jp wrote: > >> I would like to know how this could be done more elegant/pythonic. > >> > >> I have a big list (over 10.000 items) with strings (each 100 to 300 > >> chars long) and want to filter them. > >> > >> list = ..... > >> […] > > > > targets = ['Banana', 'Car'...] > > for item in list[:]: > > for target in targets: > > if target in item: > > list.remove(item) > > > >> btw: Is it correct to iterate over a copy (list[:]) of that string list > >> and not the original one? > > > > Absolutely :) > > However, “list” is a built-in class/constructor that would be overwritten > this way. One should choose another identifier than “list” for one’s > variables. > > -- > PointedEars > > Twitter: @PointedEars2 > Please do not cc me. / Bitte keine Kopien per E-Mail. > -- > https://mail.python.org/mailman/listinfo/python-list > -- Sivan Greenberg Co founder & CTO Vitakka Consulting -- https://mail.python.org/mailman/listinfo/python-list
