import re
str = '123456789983qw'
re.findall("(.{3})", str)+[str[-(len(str) % 3):]]
[EMAIL PROTECTED] wrote:
> Hi,
>
> Is there a function that split a string into groups, containing an "x"
> amount of characters?
>
> Ex.
> TheFunction("Hello World",3)
>
> Returns:
>
> ['Hell','o W','orl','d']
>
>
> Any reply would be truly appreciated.
>
> Thank You,
>
--
Best regards,
Maksim Kasimov
mailto: [EMAIL PROTECTED]
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http://mail.python.org/mailman/listinfo/python-list
