On Mon, Mar 7, 2016 at 3:21 PM, Fillmore <fillmore_rem...@hotmail.com>
wrote:
> On 3/7/2016 6:17 PM, Ian Kelly wrote:
>
>> On Mon, Mar 7, 2016 at 4:09 PM, Fillmore <fillmore_rem...@hotmail.com>
>> wrote:
>>
>>>
>>> I must be missing something simple because I can't find a way to break
>>> out
>>> of a nested loop in Python.
>>>
>>> Is there a way to label loops?
>>>
>>
>> No, you can't break out of nested loops,
>>
>
> wow...this is a bit of a WTF moment to me :(
>
> apart from structuring your
>> code such that return does what you want.
>>
>>
> Can you elaborate? apologies, but I'm new to python and trying to find my
> way out of perl....
The normal way of breaking out of some set of loops would be to structure
your code so that you have a function, and when you want to break out of
some of multiple loops, you can just call return.
As a very rough example:
def processFile(file):
for line in file:
section = line.split()
for section in line:
if sectionCorrupt:
return # Stops processing the entire file, by exiting the
function, but keeps processing the list of files.
for file in files:
processFile(file)
Alternatively, as you mention corrupted lines, perhaps raising an exception
would be the best approach.
And the same rough example, using an exception without a function:
for file in files:
try:
for line in file:
section = line.split()
for section in line:
if sectionCorrupt:
raise Exception('Section corrupt') # You probably want
more details here, for possible manual repair. You could also have a custom
exception class for more control.
except Exception as e:
print('Failed to process the file {} with error {}.'.format(file,
str(e))) # Probably should also print the entire traceback to aid in
repairing errors, especially if they are due to a bug in the code, but this
is the rough idea.
--
https://mail.python.org/mailman/listinfo/python-list
